document.write( "Question 1172651: The sum of the ages of Gerardo and Alexis is 104 years. 12 years ago, Gerardo's age was 3 times Alexis's age. How old is Gerardo now?
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Algebra.Com's Answer #797772 by ikleyn(52798) $\"\"$ $\"About$

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\n" ); document.write( "The sum of the ages of Gerardo and Alexis is 104 years. 12 years ago, Gerardo's age was 3 times Alexis's age.
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document.write( "Let x be the Alexis' age.\r\n" );
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document.write( "Then the Gerardo age is  (104-x) years.\r\n" );
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document.write( "12 years ago\r\n" );
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document.write( "    Alexis age was (x-12) years,\r\n" );
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document.write( "    Gerardo's age was  (104-x-12) = (92-x),\r\n" );
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document.write( "        and the equation states\r\n" );
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document.write( "            92 - x = 3*(x-12)\r\n" );
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document.write( "Simplify it\r\n" );
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document.write( "    92 - x = 3x - 36\r\n" );
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document.write( "    92 + 36 = 3x + x\r\n" );
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document.write( "      128   = 4x\r\n" );
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document.write( "        x   = 128/4 = 32. \r\n" );
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document.write( "ANSWER.  Gerardo's age is 104 - 32 = 72 years.\r\n" );
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