document.write( "Question 1172651: The sum of the ages of Gerardo and Alexis is 104 years. 12 years ago, Gerardo's age was 3 times Alexis's age. How old is Gerardo now?
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Algebra.Com's Answer #797766 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "I suspect the interpretation of the given information by the other tutor is not correct. \n" ); document.write( "I think the information is that Gerardo's age 12 years ago was 3 times Alexis's age 12 years ago -- not 3 times Alexis's current age.... \n" ); document.write( "12 years ago, the sum of their ages was 104-2(12) = 80. \n" ); document.write( "At that time, Gerardo was 3 times as old as Alexis. Any number of different methods can be used to determine that their ages 12 years ago were 60 and 20. \n" ); document.write( "So Gerardo's age now is 60+12 = 72. \n" ); document.write( " \n" ); document.write( " |