document.write( "Question 1172670: Quantity z varies jointly as x and the cube of y. If z = 96 when x = 2 and y = 2, find z when x = 3 and y = 3.
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Algebra.Com's Answer #797765 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


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\n" ); document.write( "(for tutor @ikleyn)....

\n" ); document.write( "... varies jointly as x and the CUBE of y..

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\n" ); document.write( "Tutor @ikleyn has provided a response showing one way (of many!) to approach a problem like this.

\n" ); document.write( "Another common method is to determine the constant of variation from the given data...
\n" ); document.write( "\"z+=+kxy%5E3\"
\n" ); document.write( "\"96+=+k%282%29%282%5E3%29+=+16k\"
\n" ); document.write( "\"k+=+96%2F16+=+6\"

\n" ); document.write( "... and then evaluate the formula with that constant and the new data.
\n" ); document.write( "\"z+=+6xy%5E3\"
\n" ); document.write( "\"z+=+6%283%29%283%5E3%29+=+6%2881%29+=+486\"

\n" ); document.write( "And here is the way I myself find easiest to use....

\n" ); document.write( "z is 96 when x is 2 and y is 2.
\n" ); document.write( "When x changes from 2 to 3, the value of z changes by a factor of 3/2.
\n" ); document.write( "When y changes from 2 to 3, the value of z changes by a factor of (3/2)^3.

\n" ); document.write( "The \"new\" value of z is

\n" ); document.write( "\"%2896%29%283%2F2%29%283%2F2%29%5E3+=+96%2881%2F16%29+=+81%2A6+=+486\"

\n" ); document.write( "Different students will find different methods more to their liking; try these different methods and find what \"works\" for you.
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