document.write( "Question 1172609: Cesar is 52 yrs younger than Melissa. 5 yrs ago, Melissas age was 3 times Cesars age. How old is Cesar? \n" ); document.write( "
Algebra.Com's Answer #797719 by Theo(13342)![]() ![]() You can put this solution on YOUR website! c = cesar's age. \n" ); document.write( "m = melissa's age. \n" ); document.write( "cesar is 52 years younger than melissa. \n" ); document.write( "equation for that is c = m - 52 \n" ); document.write( "5 years ago, melissa was 3 times as old as cesar. \n" ); document.write( "equation for that is m - 5 = 3 * (c - 5) \n" ); document.write( "simplify that equation to get m - 5 = 3 * c - 15 \n" ); document.write( "you have two equations that need to be solved simultaneously. \n" ); document.write( "they are: \n" ); document.write( "c = m - 52 \n" ); document.write( "m - 5 = 3 * c - 15 \n" ); document.write( "rearrange the equations so that the variables are on the left and the constant terms are on the right. \n" ); document.write( "you will get: \n" ); document.write( "m - c = 52 \n" ); document.write( "m - 3c = -10 \n" ); document.write( "subtract the second equation from the first to get: \n" ); document.write( "2c = 62 \n" ); document.write( "solve for c to get c = 31 \n" ); document.write( "in the equation of c = m - 52, replace c with 31 to get: \n" ); document.write( "31 = m - 52 \n" ); document.write( "add 52 to both sides of this equation to get: \n" ); document.write( "83 = m \n" ); document.write( "you have: \n" ); document.write( "c = 31 \n" ); document.write( "m = 83 \n" ); document.write( "your first original equation is satisfied because m - c = 52 becomes 83 - 31 = 52 which becomes 52 = 52 which is true. \n" ); document.write( "your second original equation is satisfied because m - 5 = 3 * (c - 5) becomes 83 - 5 = 3 * (31 - 5) which becomes 78 = 3 * 26 which becomes 78 = 78 which is true. \n" ); document.write( " \n" ); document.write( " |