document.write( "Question 109391: This is not in a textbook it's in a Math Student workbook made up by my university.
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document.write( "Jennie drives to her son's house in 5 hours when there is heavy traffic. When there is no traffic, the same trip takes 4 hours. She can drive an average of 12 m.p.h. faster when there is no traffic than when thereis heavy traffic.\r
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document.write( "What is her average speed when there is no traffic?\r
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document.write( "What is the distance from her house to her son's house? \n" );
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Algebra.Com's Answer #79769 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Jennie drives to her son's house in 5 hours when there is heavy traffic. When there is no traffic, the same trip takes 4 hours. She can drive an average of 12 m.p.h. faster when there is no traffic than when there is heavy traffic. \n" ); document.write( ": \n" ); document.write( "What is her average speed when there is no traffic? \n" ); document.write( ": \n" ); document.write( "Let s = Av speed, no traffic \n" ); document.write( "Then \n" ); document.write( "(s-12) = Av speed in traffic \n" ); document.write( ": \n" ); document.write( "The distance for both situations is given as the same: \n" ); document.write( ": \n" ); document.write( "Write a distance equation: Distance = time * speed \n" ); document.write( ": \n" ); document.write( "Dist traffic = Dist no traffic \n" ); document.write( "5(s-12) = 4s \n" ); document.write( "5s - 60 = 4s \n" ); document.write( "5s - 4s = +60 \n" ); document.write( "s = 60 mph no traffic \n" ); document.write( "and \n" ); document.write( "60 - 12 = 48 mph in traffic \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "What is the distance from her house to her son's house? \n" ); document.write( "5(48) = 240 miles \n" ); document.write( "and \n" ); document.write( "4(60) = 240 miles \n" ); document.write( " |