document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1172391>Question 1172391</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If z.x^2 - 2.y.z^2 + x.y = 0 then find partial derivative of x w.r.t z at point (1, 1, 1)?      [Here ^2 means power 2] </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #797636 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=797636\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If zx^2 - 2yz^2 + xy = 0 <BR>\n" );
document.write( "partial derivative of x with respect to z is <BR>\n" );
document.write( "2zx + y <BR>\n" );
document.write( "at (1,1,1) <BR>\n" );
document.write( "2zx + y = 3 </SPAN>\n" );
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