document.write( "Question 109407: Are the following lines parallel, perpendicular, or neither?
\n" ); document.write( " L1 with equation x – 4y = 12
\n" ); document.write( " L2 with equation 4x + y = 4
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Algebra.Com's Answer #79762 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First let's find the slope of x – 4y = 12\r
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Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)
Convert from standard form (Ax+By = C) to slope-intercept form (y = mx+b)


\"1x-4y=12\" Start with the given equation


\"1x-4y-1x=12-1x\" Subtract 1x from both sides


\"-4y=-1x%2B12\" Simplify


\"%28-4y%29%2F%28-4%29=%28-1x%2B12%29%2F%28-4%29\" Divide both sides by -4 to isolate y


\"y+=+%28-1x%29%2F%28-4%29%2B%2812%29%2F%28-4%29\" Break up the fraction on the right hand side


\"y+=+%281%2F4%29x-3\" Reduce and simplify


The original equation \"1x-4y=12\" (standard form) is equivalent to \"y+=+%281%2F4%29x-3\" (slope-intercept form)


The equation \"y+=+%281%2F4%29x-3\" is in the form \"y=mx%2Bb\" where \"m=1%2F4\" is the slope and \"b=-3\" is the y intercept.



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\n" ); document.write( "\n" ); document.write( "Now let's find the slope of 4x + y = 4\r
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Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)
Convert from standard form (Ax+By = C) to slope-intercept form (y = mx+b)


\"4x%2B1y=4\" Start with the given equation


\"4x%2B1y-4x=4-4x\" Subtract 4x from both sides


\"1y=-4x%2B4\" Simplify


The original equation \"4x%2B1y=4\" (standard form) is equivalent to \"y+=+-4x%2B4\" (slope-intercept form)


The equation \"y+=+-4x%2B4\" is in the form \"y=mx%2Bb\" where \"m=-4\" is the slope and \"b=4\" is the y intercept.



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\n" ); document.write( "\n" ); document.write( "Now multiply the slopes of \"1%2F4\" and \"-4\" to get \"%281%2F4%29%28-4%29=-4%2F4=-1\"\r
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\n" ); document.write( "\n" ); document.write( "Since the product of the two slopes is -1, the two slopes are perpendicular
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