document.write( "Question 1172530: Theresa can do a piece of work in 15 days. After she has worked 3 days, Rowena joins her and they finish work in 4 days. How long can Rowena finish the work alone? \n" ); document.write( "
Algebra.Com's Answer #797594 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Theresa working alone for 3 days completes 3/15 = 1/5 of the job; 4/5 of the job remains to be done.

\n" ); document.write( "Theresa and Rowena together complete those 4/5 of the job in 4 days; that means together they complete 1/5 of the job each day.

\n" ); document.write( "Each day Theresa alone does 1/15 of the job and together they do 1/5 of the job. That means each day Rowena does 1/5-1/15 = 3/15-1/15 = 2/15 of the job.

\n" ); document.write( "Since Rowena does 2/15 of the job each day, the number of days it would take Rowena to do the whole job alone is 15/2, or 7 1/2.

\n" ); document.write( "ANSWER: 7 and a half days

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