document.write( "Question 1172506: the 7th term of an ap is 17 and the13th term is 12 more than the 7th term find the sum of the first 18th terms of the ap \n" ); document.write( "
Algebra.Com's Answer #797589 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "There are dozens of similar ways to solve a problem like this. Here is what I would do....

\n" ); document.write( "Given:
\n" ); document.write( "Arithmetic sequence
\n" ); document.write( "7th term 17
\n" ); document.write( "13th term 12 more than the 7th term

\n" ); document.write( "To find:
\n" ); document.write( "Sum of first 18 terms

\n" ); document.write( "Solution....

\n" ); document.write( "(1) The sum of the first 18 terms of an arithmetic sequence is 18 times the average of all the terms, which in a sequence with 18 terms is 18 times the average of the 9th and 10th terms (the two terms \"in the middle\").

\n" ); document.write( "(2) The 13th term is the 7th term plus 13-7=6 times the common difference; since the 13th term is 12 more than the 7th, the common difference is 12/6 = 2.

\n" ); document.write( "(3) So the 7th, 8th, 9th, and 10th terms of the sequence are 17, 19, 21, and 23.

\n" ); document.write( "ANSWER: The sum of the first 18 terms is

\n" ); document.write( "\"18%28%2821%2B23%29%2F2%29+=+18%2822%29+=+%2820-2%29%2820%2B2%29+=+20%5E2-2%5E2+=+400-4+=+396\"

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