document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=109324>Question 109324</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395937760/algebrahomeworkh>ALGEBRA 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Two friends are 60 miles apart.  They decide to ride their bikes to meet each other.  Sally starts from the college and heads east, riding at a rate of 21 mph.  At the same time, Teresa starts from the river and heads west, riding at a rate of 15 mph.\r<BR>\n" );
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document.write( "a. draw a diagram showing the college and the river 60 miles apart and the two cyclists riding toward each other (I can do that)!\r<BR>\n" );
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document.write( "b. How far does each cyclist ride in t hours? (i need help with this one)!\r<BR>\n" );
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document.write( "c. When the two cyclists meet, what must be true about the distances they have ridden? Write and solve an equation to find when they meet.(oh boy--i need help here too)!!!\r<BR>\n" );
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document.write( "I just am not sure what to do here..I am thinking  d=r.t\r<BR>\n" );
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document.write( "               rate             distance          time<BR>\n" );
document.write( "sally          21 mph           60 miles          t<BR>\n" );
document.write( "teresa         15mps            60 miles          t\r<BR>\n" );
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document.write( "60=21t for sally<BR>\n" );
document.write( "60=15t for teresa\r<BR>\n" );
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document.write( "I am lost now.....I just don't know what to do, even if I was correct so far.... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #79758 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=79758\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Sally starts from the college and heads east, riding at a rate of 21 mph.<BR>\n" );
document.write( "At the same time, Teresa starts from the river and heads west, riding at a rate of 15 mph. <BR>\n" );
document.write( "a. draw a diagram showing the college and the river 60 miles apart and the two cyclists riding toward each other (I can do that)! <BR>\n" );
document.write( "b. How far does each cyclist ride in t hours? (i need help with this one)!<BR>\n" );
document.write( "Sally DATA:<BR>\n" );
document.write( "Rate = 21 mph; Time = t hours; Distance = rt = 21t miles<BR>\n" );
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document.write( "Theresa DATA;<BR>\n" );
document.write( "Rate = 15 mph; time =- t hours; Distance = rt = 15t<BR>\n" );
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document.write( "c. When the two cyclists meet, what must be true about the distances they have ridden? Write and solve an equation to find when they meet.(oh boy--i need help here too)!!! <BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "Sally distance + Thresa distance = 60<BR>\n" );
document.write( "21t + 15t = 60<BR>\n" );
document.write( "36t = 60<BR>\n" );
document.write( "6t = 10<BR>\n" );
document.write( "t = (5/3) hour<BR>\n" );
document.write( "t = 1 hour 40 minutes<BR>\n" );
document.write( "==================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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