document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1172464>Question 1172464</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The average age of 6 men is 49 years and the average of 5 of them is 47 years.what is the average of the sixth man? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #797501 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=797501\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is a way to solve this kind of problem that is different than the usual method shown by the other tutor.  It can be useful when the numbers being averaged are all close together.<br><BR>\n" );
document.write( "The average age of all 6 men is 49, and the average age of 5 of them is 47.<br><BR>\n" );
document.write( "Comparing the known ages to the average, the age of each of the 5 men is 2 years below the average, so the total age of those 5 men is 5*2=10 years under the average.<br><BR>\n" );
document.write( "That means the age of the 6th man must be 10 years above the average.<br><BR>\n" );
document.write( "ANSWER: The age of the 6th man is 49+10 = 59.<br><BR>\n" );
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