document.write( "Question 1172456: A lion is trying to catch an antelope. The antelope runs for 10.0 s at a constant velocity of +22.0 m/s. Starting from rest, what constant acceleration must the lion maintain in order to run the same distance as its prey(antelope) runs in the same time? (Assume that they both take a straight path) \n" ); document.write( "
Algebra.Com's Answer #797489 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "The antelope runs for 10.0 seconds at a constant velocity of 22.0 m/s
\n" ); document.write( "The distance the animal runs is 10*22 = 220 meters\r
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\n" ); document.write( "\n" ); document.write( "The lion must run 220 meters in 10 seconds. It's starting velocity is vi = 0, since it's starting from rest. The lion's goal is to catch the antelope at the very tail end of the 220 meter stretch.\r
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\n" ); document.write( "\n" ); document.write( "We can summarize what we know so far for the lion
\n" ); document.write( "x = distance = 220 meters
\n" ); document.write( "t = time = 10 seconds
\n" ); document.write( "vi = starting velocity = 0 m/s\r
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\n" ); document.write( "\n" ); document.write( "We'll use this kinematics formula
\n" ); document.write( "x = vi*t + 0.5*a*t^2\r
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\n" ); document.write( "\n" ); document.write( "Let's solve for 'a'
\n" ); document.write( "x = vi*t + 0.5*a*t^2
\n" ); document.write( "220 = 0*10 + 0.5*a*10^2
\n" ); document.write( "220 = 50a
\n" ); document.write( "50a = 220
\n" ); document.write( "a = 220/50
\n" ); document.write( "a = 4.4\r
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\n" ); document.write( "\n" ); document.write( "The lion's acceleration must be 4.4 m/s^2, and this acceleration must be constant.
\n" ); document.write( "An acceleration of 4.4 m/s^2 means the lion's velocity is increasing by 4.4 m/s for each second.\r
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\n" ); document.write( "\n" ); document.write( "Answer: 4.4 m/s^2
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