document.write( "Question 1170803: good day please may you assist me in the following \r
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document.write( "three friends A, B and C dine out an decide to spilt the bill according to what they order. A's portion and B's portion of the bill totalled $35, while B's portion of the bill was $5 less than C's portion of the bill. The ratio of A's portion to C's portion of the bill is 4:5. determine the total bill. \n" );
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Algebra.Com's Answer #797486 by mahikab(11)![]() ![]() ![]() You can put this solution on YOUR website! Given: \n" ); document.write( "(1) A:C = 4:5 \n" ); document.write( "=> A/C = 4/5 \n" ); document.write( "A = 4C/5\r \n" ); document.write( "\n" ); document.write( "(2) A + B = $35 \n" ); document.write( "Substituting the value of A from (1) above, \n" ); document.write( "4C/5 + B = 35 \n" ); document.write( "(4C/5 + B) * 5 = 35 * 5 \n" ); document.write( "4C + 5B = 175\r \n" ); document.write( "\n" ); document.write( "(3) C - B = 5 \n" ); document.write( "5 * (C - B) = 5 * 5 \n" ); document.write( "5C - 5B = 25\r \n" ); document.write( "\n" ); document.write( "Adding the equations from (2) and (3) above: \n" ); document.write( "4C + 5B = 175 \n" ); document.write( "5C - 5B = 25 \n" ); document.write( "---------------- \n" ); document.write( "9C = 200 \n" ); document.write( "C = 200/9 = $22.22\r \n" ); document.write( "\n" ); document.write( "Substituting the value of C in the equation (3), \n" ); document.write( "22.22 - B = 5 \n" ); document.write( "B = 22.22 - 5 = $17.22\r \n" ); document.write( "\n" ); document.write( "Finally from equation (1), \n" ); document.write( "A = 4C/5 = (4/5)*(200/9) = 160/9 = $17.77\r \n" ); document.write( "\n" ); document.write( "Hence the solution: \n" ); document.write( "A = $17.77 \n" ); document.write( "B = $17.22 \n" ); document.write( "C = $22.22 \n" ); document.write( " |