document.write( "Question 1172383: Two game tiles, numbered 1 through 9, are selected at random from a box without replacement. If their sum is even, what is the probability that both numbers are odd? \n" ); document.write( "
Algebra.Com's Answer #797404 by ikleyn(52787)\"\" \"About 
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document.write( "If their sum is even, it means that EITHER both numbers are odd OR both numbers are even.\r\n" );
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document.write( "Among the numbers 1 to 9 inclusive, there are 5 odd and 4 even numbers.\r\n" );
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document.write( "So,  P(the sum is even) = P(both are odd) + P(both are even) = \"%285%2F9%29%2A%284%2F8%29+%2B+%284%2F9%29%2A%283%2F8%29\" = \"20%2F72+%2B+12%2F72\" = \"32%2F72\".    \r\n" );
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document.write( "From the other hand side,  P(both are odd) = \"%285%2F9%29%2A%284%2F8%29\" = \"20%2F72\".\r\n" );
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document.write( "Therefore, the conditional probability that both numbers are odd, given that their sum is even, is equal to\r\n" );
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document.write( "    P(final) = \"P%28both_are_odd%29%2FP%28the_sum_is_even%29\" = \"%28%2820%2F72%29%29%2F%28%2832%2F72%29%29\" = \"20%2F32\" = \"5%2F8\".    ANSWER\r\n" );
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