document.write( "Question 1172368: One bag contains 4 white balls and 3 black balls, and a second bag contains 3 white
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document.write( "balls and 5 black balls. One ball is drawn from the first bag and placed unseen in
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document.write( "the second bag. What is the probability that a ball now drawn from the second
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document.write( "bag is black? \n" );
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Algebra.Com's Answer #797395 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "There are two cases to analyze: the ball drawn from the first bag can be either white or black. \n" ); document.write( "Case 1: first ball white \n" ); document.write( "P(white from first bag) = 4/7. \n" ); document.write( "There are now 4 white and 5 black in the second bag; P(black from second bag) = 5/9. \n" ); document.write( "P(white then black) = (4/7)(5/9) = 20/63. \n" ); document.write( "Case 2: first ball black \n" ); document.write( "P(black from first bag) = 3/7. \n" ); document.write( "There are now 3 white and 6 black in the second bag; P(black from second bag) = 6/9. \n" ); document.write( "P(black then black) = (3/7)(6/9) 18/63. \n" ); document.write( "ANSWER: P black from second bag = 20/63+18/63 = 38/63. \n" ); document.write( " \n" ); document.write( " |