document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1172348>Question 1172348</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the radius and center of the circle with equation:<BR>\n" );
document.write( "2x^(2)+2y^(2)+24x-81=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #797367 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=797367\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> rewrite as<BR>\n" );
document.write( "2x^2+24x+2y^2=81<BR>\n" );
document.write( "divide by 2<BR>\n" );
document.write( "x^2+12x+y^2=(81/2)<BR>\n" );
document.write( "complete the square<BR>\n" );
document.write( "x^2+12x+36+y^2=76.5<BR>\n" );
document.write( "(x+6)^2+(y+0)^2=76.5<BR>\n" );
document.write( "center is at (-6, 0) with radius sqrt(76.5);this is also 1.5 *sqrt(34)<BR>\n" );
document.write( " </SPAN>\n" );
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