document.write( "Question 1172346: To qualify for a police academy, applicants are given a test of physical fitness. The scores are normally distributed with a mean of 64 and a standard deviation of 9. If only the top 20% of the applicants are selected, find the cutoff score.
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Algebra.Com's Answer #797361 by Theo(13342)\"\" \"About 
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mean is 64
\n" ); document.write( "standard deviation is 9
\n" ); document.write( "to be in the top 20%, the z-score needs to be greater than 80%.
\n" ); document.write( "that would be the area to the left of the z-score.
\n" ); document.write( "if you look in the z-score table for an area of .8 to the left of the indicated z-score, you will find:
\n" ); document.write( "z-score is between .84 and .85.
\n" ); document.write( "interpolation yields .8416129032
\n" ); document.write( "raw score yields 71.57451613
\n" ); document.write( "that would be the score that he needs to be better than 80% of the other applicants.
\n" ); document.write( "you could save yourself a lot of grief by using a z-score calculator.
\n" ); document.write( "in that calculator, .....
\n" ); document.write( "provide the mean of 64.
\n" ); document.write( "provide the standard deviation of 9.
\n" ); document.write( "the calculator should give you the raw score indicated above, perhaps rounded a bit differently.
\n" ); document.write( "here's a picture from one of the easiest of them to use.\r
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\n" ); document.write( "\n" ); document.write( "this calculator can be found at http://davidmlane.com/hyperstat/z_table.html\r
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\n" ); document.write( "\n" ); document.write( "if you do not have access to a calculator and must use the z-score tables, then the procedure would be as shown below:\r
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\n" ); document.write( "\n" ); document.write( "look in the z-score for an area to the left of the z-score closest to .8.
\n" ); document.write( "one value above.
\n" ); document.write( "one value below.\r
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\n" ); document.write( "\n" ); document.write( "i found:
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document.write( "             z-score             area to the left\r\n" );
document.write( "                .84                  .79955\r\n" );
document.write( "                .85                  .80234\r\n" );
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document.write( "difference      .01                  .00279\r\n" );
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\n" ); document.write( "\n" ); document.write( "the area to the left of the z-score you want is .8.\r
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\n" ); document.write( "\n" ); document.write( ".8 - .79955 = .00045\r
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\n" ); document.write( "\n" ); document.write( "your ratio is:\r
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\n" ); document.write( "\n" ); document.write( "x / (.01) = .00045 / .00279\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get:\r
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\n" ); document.write( "\n" ); document.write( "x = .00045 /.00279 * .01 = .0016129032.\r
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\n" ); document.write( "\n" ); document.write( "add this to the z-score of .84 to get:
\n" ); document.write( "your z-score is .84 + .0016129032 = .8416129032.\r
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\n" ); document.write( "\n" ); document.write( "use the z-score formula to find the raw score.\r
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\n" ); document.write( "\n" ); document.write( "z = (x - m) / s becomes .8416129032 = x - 64) / 9
\n" ); document.write( "solve for x to get:
\n" ); document.write( "x = 9 * .8416129032 + 64 = 71.57451612\r
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\n" ); document.write( "\n" ); document.write( "if you round this to 3 decimal places, it will be 71.575, same as the calculator provided.\r
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\n" ); document.write( "\n" ); document.write( "the x that i used for interpolation is not the same x that i used to find the raw score.
\n" ); document.write( "same variable name used in two different procedures is acceptable.
\n" ); document.write( "they are not referring to the same thing.\r
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\n" ); document.write( "\n" ); document.write( "manual interpolation can be tricky, but it does work reasonable well.
\n" ); document.write( "with so many calculators that do z-scores and raw scores around, it's usually not necessary.\r
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