document.write( "Question 1172330: Vernon, Joshua, and Dino are painting a house. Working together they can paint the house is 6 hours. Working alone Vernon can paint the house in 15 hours and Dino can paint the house in 20 hours. How long would it take Joshua to paint the house working alone? \n" ); document.write( "
Algebra.Com's Answer #797356 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Here is an alternative to the standard algebraic solution shown by tutor @ikleyn. \n" ); document.write( "Many students prefer this method because it avoids using fractions. Note, however, that the required arithmetic is nearly the same as in the solution shown by @ikleyn. \n" ); document.write( "Consider the least common multiple of the given times. The LCM of 6, 15, and 20 is 60. \n" ); document.write( "Now see what each worker or combination of workers could do in 60 hours. \n" ); document.write( "Together the three of them in 60 hours could paint 60/6=10 houses. \n" ); document.write( "Vernon working alone in 60 hours could paint 60/15 = 4 houses. \n" ); document.write( "Dino working alone in 60 hours could paint 60/20 = 3 houses. \n" ); document.write( "That means Joshua alone in 60 hours could paint 10-4-3 = 3 houses. \n" ); document.write( "So Joshua working alone could paint the one house in 60/3 = 20 hours. \n" ); document.write( "ANSWER: 20 hours. \n" ); document.write( " \n" ); document.write( " |