document.write( "Question 1172312: The equation of catenary is given by the following second order differential equation:
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Algebra.Com's Answer #797326 by ikleyn(52781)\"\" \"About 
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document.write( "The general solution to the given differential equation is\r\n" );
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document.write( "    y(x) = 2.5x^2 + bx + c,\r\n" );
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document.write( "where b and c are unknown constant values.\r\n" );
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document.write( "To find these unknown values, use the given boundary conditions\r\n" );
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document.write( "    a)  at  x= 0       2.5*0^2 + b*0 + c = 100.2,   which gives  c = 100.2;\r\n" );
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document.write( "    b)  at  x= 100.1:  2.5*100.1^2 + b*100.1 + 100.2 = 100.1  which gives\r\n" );
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document.write( "                       25150.225 + 100.2b = 100.1\r\n" );
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document.write( "                       100.2b             = 100.1 - 25150.225 = -25050.125\r\n" );
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document.write( "                       b = -25050.125/100.2 = -250.0012475. \r\n" );
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document.write( "It gives your solution/answer.\r\n" );
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