document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1172316>Question 1172316</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Obtain the equation of the straight line passing through the point (4, 5) and<BR>\n" );
document.write( "(i) parallel to<BR>\n" );
document.write( "(ii) perpendicular to 3x-2y+5=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #797306 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=797306\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x-2y+5=0 may be rewritten as 2y=3x+5 or y=(3/2)x+(5/2).  The slope is 3/2, so any line parallel to this one has slope (3/2) and any line perpendicular to it has slope -2/3, the negative reciprocal.<BR>\n" );
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document.write( "point slope formula, y-y1=m(x-x1) m slope and (x1, y1) point<BR>\n" );
document.write( "y-5=(3/2)(x-4)<BR>\n" );
document.write( "y=(3/2)x-1. answer to i<BR>\n" );
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document.write( "y-5=(-2/3)(x-4)<BR>\n" );
document.write( "y=(-2/3)x+25/3, answer to ii<BR>\n" );
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