document.write( "Question 16312: please help me with {x+6y=2
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document.write( " {5x+4y=36 \n" );
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Algebra.Com's Answer #7973 by elima(1433) ![]() You can put this solution on YOUR website! eqn.1 x+6y=2 \n" ); document.write( "eqn.2 5x+4y=36 \n" ); document.write( "We will begin this by eliminating one variable so we can solve the other. \n" ); document.write( "Lets eliminate the x, to do that we need to multiply -5 to eqn.1 \n" ); document.write( "(-5)x+6y=2 \n" ); document.write( "-5x-30y=-10; \n" ); document.write( "Now we will add eqn.1 and eqn.2 together; \n" ); document.write( "-5x-30y=-10 \n" ); document.write( " 5x+4y=36 \n" ); document.write( "----------- \n" ); document.write( "-26y=26 \n" ); document.write( "y=-1 \n" ); document.write( "Now we have what y =, so we can plug that into either equation and find x; \n" ); document.write( "x+6(-1)=2 \n" ); document.write( "x-6=2 \n" ); document.write( "x=8 \n" ); document.write( "Now we have our answer; \n" ); document.write( "x=8, y=-1 \n" ); document.write( "Don't forget to check; \n" ); document.write( "x+6y=2 \n" ); document.write( "8+6(-1)=2 \n" ); document.write( "8-6=2 \n" ); document.write( "Hope you understand \n" ); document.write( "=) \n" ); document.write( " |