document.write( "Question 1172247: Dear tutor, Please help me solving these problems\r
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document.write( "1) An unbiased die is tossed. Find the probability that the number obtained is:
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document.write( "(a) An event number (b) Less than 4 (c) Greater than 6\r
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document.write( "2) A card is randomly drawn from a standard deck of 52 playing cards. Find the probability that the card drawn is:
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document.write( "(a) A king (b) A diamond (c) Not a diamond (d) A king of diamonds\r
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document.write( "3) A letter is randomly chosen from the word NATIONAL. What is the probability that it will be?
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document.write( "(a) The letter A (b) A vowel (c) The letter S\r
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document.write( "4) A box contains 3 red discs, 4 green discs, and 5 blue discs. One disc is randomly drawn from the box. What is probability that will be:
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document.write( "(a) red disc (b) A green disc (c) A red disc or green disc (d) Not a blue disc
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Algebra.Com's Answer #797207 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! You should only post one question at a time. I'll do the first 2 problems to get you started.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "===========================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Problem 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Part (a)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are 3 even numbers (2,4,6) out of 6 total (1 through 6). \n" ); document.write( "So 3/6 = 1/2 is the probability of rolling an even number. \n" ); document.write( "Or you could say \"half of the values are even\".\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 1/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Part (b)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We could use the same idea as part (a) above, but let's take a more formal approach. This approach is likely what many math textbooks use.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We'll use the concept of event space and sample space. \n" ); document.write( "The event space is the set of all desired outcomes. \n" ); document.write( "The sample space is the set of all possible outcomes (desired or not). \n" ); document.write( "The event space is a subset of the sample space, which means that anything in set E is also in set S, but not vice versa.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's say \n" ); document.write( "E = event space \n" ); document.write( "S = sample space \n" ); document.write( "both represent sets\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let n(E) represent the number of items in the event space. \n" ); document.write( "Let n(S) represent the number of items in the sample space.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Dividing the numbers n(E) and n(S) leads to the probability of selecting an item randomly from the event space. \n" ); document.write( "We can say \n" ); document.write( "P(E) = n(E)/n(S)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "With that bit of info in mind, we can tackle the problem.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "E = {1,2,3} = set of values we want, everything less than 4 \n" ); document.write( "S = {1,2,3,4,5,6} = set of all possible values (some values in here are what we don't want) \n" ); document.write( "everything in E is also in S, but not vice versa\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n(E) = 3 = there are 3 items in set E \n" ); document.write( "n(S) = 6 = there are 6 items in set S \n" ); document.write( "P(E) = n(E)/n(S) \n" ); document.write( "P(E) = 3/6 \n" ); document.write( "P(E) = 1/2 \n" ); document.write( "This approach may seem more tedious, but it's handy to get a formal structure of how probability is set up.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 1/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Part (c)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Event space = { } = empty set \n" ); document.write( "Sample space = {1,2,3,4,5,6} \n" ); document.write( "The event space is empty because there are no values greater than 6 on a standard die. This leads to a probability of 0 which says \"the probability of getting a value greater than 6 is impossible\".\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "More formally, \n" ); document.write( "P(E) = n(E)/n(S) \n" ); document.write( "P(E) = 0/6 \n" ); document.write( "P(E) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==============================================================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Problem 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Part (a)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Event space = {King of Hearts, King of Diamonds, King of Spades, King of Clubs} \n" ); document.write( "Sample space = {52 cards in a standard deck} \n" ); document.write( "We have 4 items in the event space, out of 52 items in the sample space. \n" ); document.write( "We get 4/52 = 1/13.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 1/13\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Part (b)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are 13 diamond cards out of 52 total. \n" ); document.write( "We get the probability 13/52 = 1/4 \n" ); document.write( "You could also look at it like \"there is one diamond suit out of 4 suits total\".\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 1/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Part (c)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We'll use the result from part (b). Subtract it from 1 \n" ); document.write( "This works because both events \"getting diamonds\" and \"getting not diamonds\" are complementary. \n" ); document.write( "You either get a diamond or you don't. \n" ); document.write( "P(not diamonds) = 1 - P(diamonds) \n" ); document.write( "P(not diamonds) = 1 - 1/4 \n" ); document.write( "P(not diamonds) = 3/4 \n" ); document.write( "We can confirm this by noting there are 3 suits that aren't diamond out of 4 suits total.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 3/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Part (d)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There's one card that is a king of diamonds out of 52 total.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 1/52 \n" ); document.write( " |