document.write( "Question 1172152: The point P lies on the line joining A(-1,-5) and B(11,13) such that AP=(1/3)AB.
\n" ); document.write( "(i) Find the equation of the line perpendicular to AB and passing through P.
\n" ); document.write( "The line perpendicular to AB passing through P and the line parallel to the
\n" ); document.write( "x-axis passing through B intersect at the point Q. \r
\n" ); document.write( "\n" ); document.write( "(ii) Find the coordinates of the point Q. \n" ); document.write( "
Algebra.Com's Answer #797192 by Boreal(15235)\"\" \"About 
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the equation of AB: slope is 3/2 and point slope y-y1=m(x-x1), m slope (x1, y1) point is
\n" ); document.write( "y+5=(3/2)(x+1)
\n" ); document.write( "y=(3/2)x-7/2
\n" ); document.write( "The line perpendicular to AB has slope -2/3.
\n" ); document.write( "AP is 4 x units or x=+3 from A and 6 y units or +1 from A.
\n" ); document.write( "so P is at (3, 1)
\n" ); document.write( "So AP has equation y-1=(-2/3) (x-3)
\n" ); document.write( "y=(-2/3)x+3
\n" ); document.write( "graph these
\n" ); document.write( "\"graph%28500%2C500%2C-15%2C15%2C-15%2C15%2C11%2C1%2C%281.5x-7%2F2%29%2C%28-2%2F3%29x%2B3%29\"\r
\n" ); document.write( "\n" ); document.write( "Point Q has y=11 and is on line y=(-2/3)x+3, so 8=(-2/3)x and x=-12
\n" ); document.write( "(-12, 11)
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