document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=109336>Question 109336</A>: <I><SPAN STYLE=\"word-break: break-all;\"> C-2 Plumbing-A 4-ft-high cylindrical pipe has a diameter of 3 in. If water weighs 62.4 lb/ft^3(cubed), what is the weight of water in the pipe when filled to the top?(Hint: Change the diameter to feet.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #79718 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=79718\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> AREA OF THE PIPE IN FEET=PI*R^2<BR>\n" );
document.write( "A=3.14(.5*3/12)^2 [3 INCHES =3/12 FEET & RADIUS =.5*DIAMETER.]<BR>\n" );
document.write( "A=3.14(1/8)^2<BR>\n" );
document.write( "A=3.14*1/64<BR>\n" );
document.write( "A=.049 SQFT.<BR>\n" );
document.write( "VOLUME=BASE*HEIGHT<BR>\n" );
document.write( "V=.049*4<BR>\n" );
document.write( "V=.196 CUBIC FEET.<BR>\n" );
document.write( "WEIGHT=.196*62.4<BR>\n" );
document.write( "W=12.246POUNDS. </SPAN>\n" );
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