document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=109256>Question 109256</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor completely.\r<BR>\n" );
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document.write( "5y^5 + 135y^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #79716 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=79716\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> :<BR>\n" );
document.write( "5y^5 + 135y^2<BR>\n" );
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document.write( "Factor out 5y^2 and you have:<BR>\n" );
document.write( "5y^2(y^3 + 27) <BR>\n" );
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document.write( "Can you recognize the \"Sum of Cubes\" in this?<BR>\n" );
document.write( "Use special factoring to factor (y^3 + 27):<BR>\n" );
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document.write( "(5y^2)(y + 3)(y^2 - 3y + 9)<BR>\n" );
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document.write( "If you are not familiar with this, look up \"Sum of Cubes\" or \"Difference of Cubes\"<BR>\n" );
document.write( "in the index of your book and learn it. </SPAN>\n" );
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