document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1172075>Question 1172075</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Consider the function f(x) = x^5 + 8x^2. Determine the number of zeros of the function after the function f(x) has been vertically stretched by a factor of 3 and vertically translated one unit up. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #797138 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=797138\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> no sign change in f(x) so no positive zeros<BR>\n" );
document.write( "one sign change in f(-x) so one negative zero.<BR>\n" );
document.write( "factoring the function into x^2(x^3+8), there is a zero at -2 and a bounce at the origin.<BR>\n" );
document.write( "Translating it up 1 unit will remove the bounce and shift the zero but not remove it<BR>\n" );
document.write( "There is one negative zero.\r<BR>\n" );
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