document.write( "Question 1172158: A spherical snowball is melting in such a way that its surface area decreases at the rate of 1 in 2 /min . How fast is its volume shrinking when its radius is 3 in ?
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Algebra.Com's Answer #797124 by math_helper(2461)![]() ![]() You can put this solution on YOUR website! Assuming that \"1 in 2/min\" is supposed to be \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( "V in terms of A: \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( "Taking the derivative of V wrt A: \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( "Need an expression for dV/dt in terms of information given: \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( "At r=3, A= \n" ); document.write( "dA/dt is given as \r \n" ); document.write( "\n" ); document.write( "So, finally, \n" ); document.write( "\n" ); document.write( "----- \n" ); document.write( "----- \n" ); document.write( "Another approach would be to use 'r' instead of 'A': dV/dt = (dV/dr)*(dr/dt) \n" ); document.write( "It is about equally messy to go this route. Because you are given dA/dt, you \n" ); document.write( " have the additional step dr/dt = (dA/dt)*(dr/dA), so dV/dt = (dV/dr)*(dA/dt)*(dr/dA) \r \n" ); document.write( "\n" ); document.write( "---- \n" ); document.write( "Dear student: Please do not use the \"thank you\" message system to post additional problems. Please post your questions (one at a time) using \n" ); document.write( "the normal process. Thank you.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |