document.write( "Question 1172177: 2. When the sum of 3 and twice a positive number is subtracted from the square of the number, the result is 0. Find the number. Show clear solution thanksss! \n" ); document.write( "

Algebra.Com's Answer #797115 by math_helper(2461) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( "Saw an error in tutor Cromlix' answer, so came in to show the fix:
\r
\n" ); document.write( "\n" ); document.write( "The expression should be:
\n" ); document.write( " $\"+x%5E2+-+%282x+%2B+3%29+=+0+\"$ , leading to...
\r
\n" ); document.write( "\n" ); document.write( " $\"+x%5E2+-+2x+-+3+=+0+\"$
\n" ); document.write( " $\"+%28x-3%29%28x%2B1%29+=+0+\"$
\r
\n" ); document.write( "\n" ); document.write( "x=3 and/or x=-1\r
\n" ); document.write( "\n" ); document.write( "Keeping just the positive answer, $\"+highlight%28+x=3+%29+\"$ \r
\n" ); document.write( "\n" ); document.write( "--------------------------------
\n" ); document.write( "Tutor Cromlix tried to fix his answer, and while he arrives at the correct answer of x=3 this time, his steps still contain several errors:\r
\n" ); document.write( "\n" ); document.write( "


\n" );
document.write( "Hi there,
\n" );
document.write( "Making x the positive number
\n" );
document.write( "x^2 - 3 + 2x = 0          <<< should be  x^2 - 3 - 2x = 0
\n" );
document.write( "Rearrange
\n" );
document.write( "x^2 - (2x - 3) = 0 
\n" );
document.write( "x^2 - 2x + 3 = 0          
\n" );
document.write( "Factorise
\n" );
document.write( "(x + 1)(x - 3) = 0        <<< this is NOT the correct factorization of x^2-2x+3, rather is is the correct factorization of x^2-2x-3 
\n" );
document.write( "x + 1 = 0
\n" );
document.write( "x = -1
\n" );
document.write( "x - 3 = 0
\n" );
document.write( "x = 3 (Disregard as negative)    <<<  left over from before his edits (??)
\n" );
document.write( "x = 3 is the answer.        <<< yes, correct
\n" );
document.write( "Hope this helps :-)  \r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "

\n" );