document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1172177>Question 1172177</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2. When the sum of 3 and twice a positive number is subtracted from the square of the number, the result is 0. Find the number. Show clear solution thanksss! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #797114 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=797114\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "Making x the positive number<BR>\n" );
document.write( "x^2 - 3 + 2x = 0<BR>\n" );
document.write( "Rearrange<BR>\n" );
document.write( "x^2 - (2x - 3) = 0<BR>\n" );
document.write( "x^2 - 2x + 3 = 0<BR>\n" );
document.write( "Factorise<BR>\n" );
document.write( "(x + 1)(x - 3) = 0 <BR>\n" );
document.write( "x + 1 = 0<BR>\n" );
document.write( "x = -1<BR>\n" );
document.write( "x - 3 = 0<BR>\n" );
document.write( "x = 3 (Disregard as negative)<BR>\n" );
document.write( "x = 3 is the answer.<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );