document.write( "Question 1171969: A psychologist finds that the intelligence quotients of a group of patients are
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document.write( "normally distributed, with a mean of 102 and a standard deviation of 16. Find
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document.write( "the percent of the patients with IQs
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document.write( "a) above 114.
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document.write( "b) between 90 and 118. \n" );
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Algebra.Com's Answer #797056 by VFBundy(438)![]() ![]() You can put this solution on YOUR website! a) above 114 \n" ); document.write( " \n" ); document.write( "z-score = \n" ); document.write( " \n" ); document.write( "A z-score of 0.75 is 0.7734. This means 77.34% of patients have an IQ below 114. To find the percentage of people with IQs above 114, subtract this from 1. This result is 22.66%. Therefore, 22.66% of patients have an IQ above 114. \n" ); document.write( " \n" ); document.write( "-------------------------------------------------------- \n" ); document.write( " \n" ); document.write( "b) between 90 and 118 \n" ); document.write( " \n" ); document.write( "z-score1 = \n" ); document.write( " \n" ); document.write( "A z-score of 1.00 is 0.8413. This means 84.13% of patients have an IQ below 118. \n" ); document.write( " \n" ); document.write( "z-score2 = \n" ); document.write( " \n" ); document.write( "A z-score of -0.75 is 0.2266. This means 22.66% of patients have an IQ below 90. \n" ); document.write( " \n" ); document.write( "To find the percentage of patients with IQs between 90 and 118, subtract 22.66% from 84.13%. This result is 61.47%. Therefore, 61.47% of the patients have an IQ between 90 and 118. |