document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1172127>Question 1172127</A>: <I><SPAN STYLE=\"word-break: break-all;\">  TEAM OF 5 IS TO BE CHOSEN FROM 4 MEN AND 5 WOMEN TO WORK ON SPECIAL PROJECT.<BR>\n" );
document.write( "1. In how many ways can the team be chosen?<BR>\n" );
document.write( "2.In how many ways can the team be chosen to include just 3 women?<BR>\n" );
document.write( "3.what is the probability that the team includes at least 3 women?<BR>\n" );
document.write( "4.What is the probability that the team includes more men than women </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #797037 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=797037\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> total number of ways is 9C5=126<BR>\n" );
document.write( "with 3 women it would be 5C3*4C2=60 ways<BR>\n" );
document.write( "at least 3 women is 60 (for 3) 5C4*4C1 or 20 (for 4) and 1 for 5, 81 ways for at least 3 women.<BR>\n" );
document.write( "more men than women is at least 3 men.<BR>\n" );
document.write( "that is 4C3*5C2=40 ways plus 4C4*5C1=5 ways<BR>\n" );
document.write( "All this add to 126 and include all the possibilities. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );