document.write( "Question 1172096: Rachel will rent a car for the weekend. She can choose one of the two plans. The first plan has an initial fee of $48 and costs an additional $0.16 per mile driven. The second plan has an initial fee of $57 and costs an additional $0.14 per mile driven. \r
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document.write( "For what amount of driving do the two plans cost the same? \r
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document.write( "What is the cost when the two plans cost the same? \n" );
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Algebra.Com's Answer #797013 by Theo(13342)![]() ![]() You can put this solution on YOUR website! plan 1 cost = 48 + .16 * x \n" ); document.write( "plan 2 cost = 57 + .14 * x \n" ); document.write( "x is the number of miles. \n" ); document.write( "plan 1 cost will be the same as plan 2 cost when: \n" ); document.write( "48 + .16 * x = 57 + .14 * x \n" ); document.write( "subtract .14 * x from both sides of the equation and subtract 48 from both sides of the equation to get: \n" ); document.write( ".16 * x - .14 * x = 57 - 48 \n" ); document.write( "combine like terms to get: \n" ); document.write( ".02 * x = 9 \n" ); document.write( "divide both sides of the equation by .02 to get: \n" ); document.write( "x = 9 / .02 = 450 \n" ); document.write( "the two plans should break even at 450 miles driven. \n" ); document.write( "at 450 miles driven,..... \n" ); document.write( "plan 1 cost = 48 + .16 * 450 = 120. \n" ); document.write( "plan 2 cost = 57 + .14 * 450 = 120.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your solution is: \n" ); document.write( "the plans will cost the same when 450 miles have been driven. \n" ); document.write( "the cost when both plans cost the same is 120 collars.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |