document.write( "Question 16346: I have a problem 3x^0+(3x)^0. I am having a hard time figuring this problem out. Your help would greatly be appreicated. \n" ); document.write( "
Algebra.Com's Answer #7970 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Any non-zero number raised to the zero power is 1. So x^0=1, y^0=1, (3x)^0 =1, (Junk)^0 = 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "However, in the case of 3x^0 where there are no parentheses, ONLY the x is raised to the zero power. So what you have is 3 times x^0, which is 3* 1=3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, in answer to your question: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " \n" ); document.write( " |