document.write( "Question 1172028: The mean length of certain bar for construction is supposed
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document.write( "to be 43mm. There is a concern that the length has changed,
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document.write( "12 bars were selected at random for a study. The following lengths were recorded: 44, 39, 45, 43, 40, 39, 41, 40, 42, 43, 42, 42 in mm. \r
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document.write( "Do you agree that there has been a change in the mean length? Use α= 1%
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Algebra.Com's Answer #796945 by Theo(13342) You can put this solution on YOUR website! the mean is supposed to be 43. \n" ); document.write( "you find the mean of the sample to be equal to 41.66666 \n" ); document.write( "you find the standard deviation of the sample to be 1.92275 \n" ); document.write( "the sample size is 12 elements. \n" ); document.write( "the standard error is equal to the standard deviation of the sample divided by the sample size = 1.92275 / sqrt(12) = .55505 \n" ); document.write( "the t-score with 11 degrees of freedom is equal to (41.66666 - 43) / .55505 = -2.40219. \n" ); document.write( "the area to the left of a t-score of -2.40219 with 11 degrees of freedom is equal to .017548. \n" ); document.write( "this is greater than .01 if a one tailed test, or .005 if a two tailed test. \n" ); document.write( "therefore, there is not enough evidence to determine that the actual mean is not 43. \n" ); document.write( "the difference is determined to be due to random variation in the mean of a sample of size 12.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |