document.write( "Question 109196: I need help solving this equation:
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document.write( " 5 over y - 3 = y + 7 over 2y - 6 plus 1 \n" );
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Algebra.Com's Answer #79691 by edjones(8007)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "5(2y-6)=(y+7)(y-3)+(y-3)(2y-6) multiply each side by (y-3)(2y-6) to eliminate fractions. \n" ); document.write( "10y-30=y^2+4y-21+2y^2-12y+18 \n" ); document.write( "10y-30=3y^2-8y-3 \n" ); document.write( "3y^2-18y-27=0 \n" ); document.write( "3(y^2-6y-9)=0 \n" ); document.write( "(y-3)(y-3)=0 \n" ); document.write( "y=3 \n" ); document.write( "Since y=3 causes division by zero in the original equation there is no answer. \n" ); document.write( "Ed \n" ); document.write( " |