document.write( "Question 1171946: A wire is 28 feet long. It is cut into three pieces. The longest piece is twice as long as the shortest piece and the remaining piece is four feet longer than the shortest piece. Find the length of each piece \n" ); document.write( "
Algebra.Com's Answer #796859 by ankor@dixie-net.com(22740)\"\" \"About 
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A wire is 28 feet long. It is cut into three pieces.
\n" ); document.write( "a + b + c = 28
\n" ); document.write( "The longest piece is twice as long as the shortest piece
\n" ); document.write( "a = 2c
\n" ); document.write( " and the remaining piece is four feet longer than the shortest piece.
\n" ); document.write( "b = c + 4
\n" ); document.write( "Replace a with 2c, and b with (c+4) in the first equation
\n" ); document.write( "2c + (c+4) + c = 28
\n" ); document.write( "4c = 28 - 4
\n" ); document.write( "4c = 24
\n" ); document.write( "c = 24/4
\n" ); document.write( "c = 6 ft is the shortest
\n" ); document.write( ":
\n" ); document.write( "Find the length of each piece
\n" ); document.write( "a = 2(6)
\n" ); document.write( "a = 12 ft is the longest
\n" ); document.write( "and
\n" ); document.write( "b = 6 + 4
\n" ); document.write( "b = 10 ft is the remaining piece
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check 12 + 10 + 6 = 28 \n" ); document.write( "
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