document.write( "Question 1171933: PLEASE HELPPPPPP
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document.write( "Brand X sells 32 oz. bags of mixed nuts
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document.write( "that contain 52% peanuts. To make their
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document.write( "product they add peanuts to Brand A's
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document.write( "mixed nuts which contain 20% peanuts.
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document.write( "How much of each do they combine? \n" );
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Algebra.Com's Answer #796840 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 32 oz*0.52 (peanuts)=16.64 oz peanuts. That is the goal. \n" ); document.write( "x oz *0.20 (peanuts) is Brand A, so that is 0.20x oz peanuts \n" ); document.write( "they are going to add pure peanuts or 100%, and it is 32-x oz of it, so the total amount is 32 oz. \n" ); document.write( "- \n" ); document.write( "Therefore, pure peanuts, which is 16.64 oz in the final product=0.20x + 32-x \n" ); document.write( "-15.36=-0.8x. Both sides negative so both sides are positive, too. \n" ); document.write( "x=15.36/0.8=19.2 oz of the 20% or 3.84 oz pure peanuts \n" ); document.write( "32-x is=12.8 oz of the pure peanuts, so that 3.84+12.8=16.64 oz peanuts. \n" ); document.write( "- \n" ); document.write( "Combine 19.2 oz brand A with 12.8 oz peanuts. \n" ); document.write( " |