document.write( "Question 109247: 1/3(9b+1)=b-1 \n" ); document.write( "

Algebra.Com's Answer #79682 by edjones(8007) $\"\"$ $\"About$

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1/3(9b+1)=b-1
\n" ); document.write( "3*(1/3(9b+1)=3(b-1) get rid of fraction.
\n" ); document.write( "9b+1=3b-3
\n" ); document.write( "9b-3b+1-1=3b-3b-3-1
\n" ); document.write( "6b=-4
\n" ); document.write( "6b/6=-4/6
\n" ); document.write( "b=-2/3
\n" ); document.write( "Ed \n" ); document.write( "

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