document.write( "Question 1171867: To greet the 2020 SHS Graduates, a tarpaulin is to be set up along the national highway.If the area of the tarp is to be 35/4 m^2 and its perimeter is 27/2 meters, what should be the dimensions of the tarpaulin? Please help me answer this question. Arigathanks in advance.
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Algebra.Com's Answer #796813 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "To greet the 2020 SHS Graduates, a tarpaulin is to be set up along the national highway.If the area of the tarp is to be 35/4 m^2 and its perimeter is 27/2 meters, what should be the dimensions of the tarpaulin? Please help me answer this question. Arigathanks in advance.
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Let the width and length be W, and L, respectively
\n" ); document.write( "Then we get:
\n" ); document.write( "\"matrix%281%2C3%2C+LW%2C+%22=%22%2C+35%2F4%29\"
\n" ); document.write( "\"matrix%281%2C3%2C+%2827%2F4+-+W%29W%2C+%22=%22%2C+35%2F4%29\" ------ Substituting \"27%2F4+-+W\" for L
\n" ); document.write( "\"matrix%281%2C3%2C+27W%2F4+-+W%5E2%2C+%22=%22%2C+35%2F4%29\"
\n" ); document.write( "\"matrix%281%2C3%2C+27W+-+4W%5E2%2C+%22=%22%2C+35%29\" ------- Multiplying by LCD, 4
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\n" ); document.write( "4W(W - 5) - 7(W - 5) = 0
\n" ); document.write( "(4W - 7)(W - 5) = 0
\n" ); document.write( "4W - 7 = 0 OR W - 5 = 0
\n" ); document.write( "4W = 7 OR W = 5
\n" ); document.write( "Width or \"highlight_green%28matrix%281%2C6%2C+W%2C+%22=%22%2C+7%2F4%2C+or%2C+1.75%2C+m%29%29\"
\n" ); document.write( "If width = \"matrix%281%2C2%2C+7%2F4%2C+m%29\", length, or
\n" ); document.write( "This can be VICE-VERSA as well, so \n" ); document.write( "
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