document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1171897>Question 1171897</A>: <I><SPAN STYLE=\"word-break: break-all;\"> B. Solve the ff. problems.\r<BR>\n" );
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document.write( "Find three consecutive integers such that the sum of the first, twice the second, and three times the third is -76. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #796799 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=796799\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "x + 2(x+1) + 3(x+2) = -76<BR>\n" );
document.write( "x + (2x+2) + (3x+6) = -76<BR>\n" );
document.write( "6x + 8 = -76<BR>\n" );
document.write( "6x = -84<BR>\n" );
document.write( "x = -14 -->  the three integers are  -14, -13, and -12\r<BR>\n" );
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