document.write( "Question 1171865:
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\n" ); document.write( "Use the sample data and confidence level given below to complete parts​ (a) through​ (d).
\n" ); document.write( "A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,
\n" ); document.write( "n=943 and x=579 who said​ \"yes.\" Use a 99% confidence level.\r
\n" ); document.write( "\n" ); document.write( "a) Find the best point estimate of the population proportion p.
\n" ); document.write( "b)Identify the value of the margin of error E.
\n" ); document.write( "c) Construct the confidence interval.
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Algebra.Com's Answer #796786 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Part (a)
\n" ); document.write( "The best estimate for the population proportion p is the sample proportion phat (read as \"p-hat\")\r
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\n" ); document.write( "\n" ); document.write( "In this case,
\n" ); document.write( "phat = (number of yes responses)/(number total)
\n" ); document.write( "phat = x/n
\n" ); document.write( "phat = 579/943
\n" ); document.write( "phat = 0.61399787910922
\n" ); document.write( "phat = 0.614
\n" ); document.write( "Which is approximate.\r
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\n" ); document.write( "Part (b)\r
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\n" ); document.write( "\n" ); document.write( "At 99% confidence, the z critical value is roughly z = 2.576\r
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\n" ); document.write( "\n" ); document.write( "The margin of error is
\n" ); document.write( "E = z*sqrt(phat*(1-phat)/n)
\n" ); document.write( "E = 2.576*sqrt(0.61399787910922*(1-0.61399787910922)/943)
\n" ); document.write( "E = 0.040838360004
\n" ); document.write( "E = 0.04
\n" ); document.write( "This is approximate. \r
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\n" ); document.write( "Part (c)\r
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\n" ); document.write( "\n" ); document.write( "We'll use the results of parts (a) and (b)\r
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\n" ); document.write( "\n" ); document.write( "The lower boundary L of the confidence interval is
\n" ); document.write( "L = (center) - (margin of error)
\n" ); document.write( "L = (phat) - (E)
\n" ); document.write( "L = 0.61399787910922 - 0.040838360004
\n" ); document.write( "L = 0.57315951910522
\n" ); document.write( "L = 0.5732\r
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\n" ); document.write( "\n" ); document.write( "And the upper boundary U is
\n" ); document.write( "L = (center) + (margin of error)
\n" ); document.write( "L = (phat) + (E)
\n" ); document.write( "L = 0.61399787910922 + 0.040838360004
\n" ); document.write( "L = 0.65483623911322
\n" ); document.write( "L = 0.6548\r
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\n" ); document.write( "\n" ); document.write( "The 99% confidence interval in the form L < p < U is roughly 0.5732 < p < 0.6548\r
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\n" ); document.write( "\n" ); document.write( "We can write this as (0.5732, 0.6548)\r
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\n" ); document.write( "\n" ); document.write( "We are 99% confident that the population proportion p is between 0.5732 and 0.6548
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