document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1166536>Question 1166536</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 8. The official distance between the home plate and the second base in a<BR>\n" );
document.write( "baseball diamond is 120 ft. find the area of the official ball diamond and the distance<BR>\n" );
document.write( "between the bases. ( note: the official diamond is in the form of a square) </SPAN>\n" );
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document.write( "It is 90ft between bases (home to 1st, 1st to 2nd, etc.) so<BR>\n" );
document.write( "the area is just one of these sides squared: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90ft%2A90ft+=+highlight%288100ft%5E2%29+ ALIGN=MIDDLE  ALT=\"90ft%2A90ft+=+highlight%288100ft%5E2%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br>\r<BR>\n" );
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document.write( "The precise length from home plate to 2nd base is  90ft*<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282%29 ALIGN=MIDDLE  ALT=\"sqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > or approximately 127ft 3in  \r<BR>\n" );
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document.write( "Not sure where the 120ft came from, unless you are talking about an \"unofficial\" baseball diamond.\r<BR>\n" );
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document.write( "For a square with diagonal measure 120ft, the side length is 120/<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282%29 ALIGN=MIDDLE  ALT=\"sqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 84.853ft and the area of such square is 7200<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ft%5E2 ALIGN=MIDDLE  ALT=\"ft%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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