document.write( "Question 1171647: The height of adult males in Japan is approximately normally
\n" );
document.write( "distributive with mean 68.5 inches and standard deviation of 1.7 inches.
\n" );
document.write( "(These numbers are fictious.)
\n" );
document.write( "(a) What percent of Japanese adult males have a height between 68
\n" );
document.write( "inches and 69.2 inches?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #796767 by Boreal(15235) You can put this solution on YOUR website! z=(x-mean)/sd \n" ); document.write( "z68 is -0.5/1.7 or -0.29 \n" ); document.write( "z69.2 is 0.7/1.7 or +0.41 \n" ); document.write( "that probability of z in between these is 0.2732 or 27.3%\r \n" ); document.write( "\n" ); document.write( "unrounded may use 2nd VARS2normalcdf(68,69.2,68.5,1.7)ENTER and get 0.2754 or 27.5%. Usually, z values to two decimal places have been used, but that was in the pre-calculator era. \n" ); document.write( " |