document.write( "Question 1171828: A fabric store sells two types of ribbon. One customer buys 3 rolls of the lace ribbon and 2 rolls of the satin ribbon and has a total of 120 yards of ribbon. Another customer buys 2 rolls of the lace ribbon and 4 rolls of the satin ribbon and has a total of 160 yards of ribbon.\r
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Algebra.Com's Answer #796726 by ikleyn(52787) $\"\"$ $\"About$

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document.write( "    3x + 2y = 120   (1)\r\n" );
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document.write( "    2x + 4y = 160   (2)\r\n" );
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document.write( "Divide eq(2) by 2 (both sides). Keep equation (1) as is.  You will get\r\n" );
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document.write( "    3x + 2y = 120   (1')\r\n" );
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document.write( "     x + 2y =  80   (2')\r\n" );
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document.write( "Now subtract eq(2') from eq(1').  You will get\r\n" );
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document.write( "    2x      = 120 - 80 = 40\r\n" );
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document.write( "     x =               = 40/2 = 20.\r\n" );
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document.write( "Then from equation (2'),  \r\n" );
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document.write( "    20 + 2y = 80\r\n" );
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document.write( "         2y = 80 - 20 = 60\r\n" );
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document.write( "          y            = 60/2 = 30.\r\n" );
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document.write( "ANSWER.   20 yards in the lace ribbon roll and 30 yards in the satin ribbon roll.\r\n" );
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