Algebra.Com's Answer #796707 by ikleyn(52943)![\"\"](\"/images/stars/stars-13.gif\")  
You can put this solution on YOUR website!
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document.write( " In his post, @josgarithmetic offers you to solve this equation  .\r
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document.write( " This equation is INCORRECT, so you better IGNORE it, for your safety :  .\r
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document.write( "The correct equation is\r\n" );
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document.write( "  +  =  ,\r\n" );
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document.write( "or, equivalently,\r\n" );
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document.write( " + =  . (1)\r\n" );
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document.write( "At this point a person familiar with arithmetic operations on fractions just can to guess the solution\r\n" );
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document.write( "w= 3, since  +  = .\r\n" );
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document.write( "But if you want to have full formal algebraic solution, let's do it step by step.\r\n" );
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document.write( "Multiply equation (1) by 6w*(w-1) (both sides). You will get then \r\n" );
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document.write( " 6w + 6*(w-1) = 5w*(w-1)\r\n" );
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document.write( " 6w + 6w - 6 = 5w^2 - 5w\r\n" );
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document.write( " 5w^2 - 17w + 7 = 0\r\n" );
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document.write( " (w-3)*(5w+2) = 0.\r\n" );
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document.write( "It has two roots, one positive and one negative.\r\n" );
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document.write( "Only positive root w= 3 is the solution to the problem,\r\n" );
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document.write( "confirming that my earlier guess was correct.\r\n" );
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document.write( "ANSWER. Winter makes the job in 3 hours; Gabo makes it in 2 hours.\r\n" );
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document.write( "To see other similar solved problems, look into the lesson\r
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document.write( " - Using quadratic equations to solve word problems on joint work \r
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document.write( "in this site.\r
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document.write( "Learn the subject from there.\r
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document.write( "Happy learning (!)\r
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document.write( "After my notice, @josgarithmetic changed his post.\r
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