document.write( "Question 1171785: The product of two consecutive integers is 71 more than their sum. Find the integers. \n" ); document.write( "

Algebra.Com's Answer #796701 by ikleyn(52797) $\"\"$ $\"About$

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document.write( "    xy = x + y + 71.\r\n" );
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document.write( "It implies\r\n" );
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document.write( "    xy - x - y + 1 = 72\r\n" );
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document.write( "    (x-1)*(y-1) = 72.\r\n" );
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document.write( "It has two basic solutions\r\n" );
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document.write( "         a)  x-1 = 8,  y-1 = 9,   which implies  x= 9, y= 10\r\n" );
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document.write( "    and\r\n" );
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document.write( "         b)  x-1 = -8,  y-1 = -9, which implies x= -7,  y= -8.\r\n" );
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document.write( "ANSWER.  There are two pairs of such integer numbers.\r\n" );
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document.write( "         One pair is  (9,10).  The other pair is (-8,-7).\r\n" );
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document.write( "CHECK.   9*10 - 9 - 10 = 90 - 19 = 71.    ! Correct !\r\n" );
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document.write( "         (-8)*(-7) - (-8) - (-7) = 56 + 8 + 7  = 71.    ! Correct !\r\n" );
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\n" ); document.write( "\n" ); document.write( "I hope I impressed you by my solution (!)\r
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