document.write( "Question 1171738: Kenneth was born 6 years before bea. In 2007, Kenneth's age was 2 years more than four times the age of Bea in 2002. How old will Bea be in 2017?\r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #796691 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let k = Kenneth's age \n" ); document.write( "let b = Bea's age \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement \n" ); document.write( ": \n" ); document.write( " Kenneth was born 6 years before bea. \n" ); document.write( "k = b + 6 \n" ); document.write( "In 2007, Kenneth's age was 2 years more than four times the age of Bea in 2002. \n" ); document.write( "In 2007: \n" ); document.write( "k = 4(b-5) + 2 \n" ); document.write( "k = 4b - 20 + 2 \n" ); document.write( "k = 4b - 18 \n" ); document.write( "replace k with (b+6) \n" ); document.write( "b + 6 = 4b - 18 \n" ); document.write( "6 + 18 = 4b - b \n" ); document.write( "24 = 3b \n" ); document.write( "b = 24/3 \n" ); document.write( "b = 8 years old in 2007 \n" ); document.write( " How old will Bea be in 2017? \n" ); document.write( "10 years from 2007 Bea will be 18 \n" ); document.write( " |