document.write( "Question 1171738: Kenneth was born 6 years before bea. In 2007, Kenneth's age was 2 years more than four times the age of Bea in 2002. How old will Bea be in 2017?\r
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Algebra.Com's Answer #796691 by ankor@dixie-net.com(22740)\"\" \"About 
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let k = Kenneth's age
\n" ); document.write( "let b = Bea's age
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\n" ); document.write( "Write an equation for each statement
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\n" ); document.write( " Kenneth was born 6 years before bea.
\n" ); document.write( "k = b + 6
\n" ); document.write( "In 2007, Kenneth's age was 2 years more than four times the age of Bea in 2002.
\n" ); document.write( "In 2007:
\n" ); document.write( "k = 4(b-5) + 2
\n" ); document.write( "k = 4b - 20 + 2
\n" ); document.write( "k = 4b - 18
\n" ); document.write( "replace k with (b+6)
\n" ); document.write( "b + 6 = 4b - 18
\n" ); document.write( "6 + 18 = 4b - b
\n" ); document.write( "24 = 3b
\n" ); document.write( "b = 24/3
\n" ); document.write( "b = 8 years old in 2007
\n" ); document.write( " How old will Bea be in 2017?
\n" ); document.write( "10 years from 2007 Bea will be 18
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