document.write( "Question 109280: two pipes togather can fill a large tank in 10hrs. one of the pipes , used alone , takes 15hrs longer than the other to fill the tank . hown long would each pipe take to fill the tank alone? \n" ); document.write( "
Algebra.Com's Answer #79667 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! two pipes togeather can fill a large tank in 10hrs \n" ); document.write( "---------. \n" ); document.write( "Together DATA: \n" ); document.write( "Time = 10 hrs/job ; Rate = 1/10 job/hr \n" ); document.write( "-------------------- \n" ); document.write( "one of the pipes , used alone , takes 15hrs longer than the other to fill the tank . \n" ); document.write( "1st pipe DATA; \n" ); document.write( "Time = x hrs/job ; Rate = 1/x job/hr \n" ); document.write( "------------ \n" ); document.write( "2nd pipe DATA: \n" ); document.write( "Time = x+15 hrs/job ; Rate = 1/(x+15) job/hr \n" ); document.write( "------------------- \n" ); document.write( "how long would each pipe take to fill the tank alone? \n" ); document.write( "--------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "rate + rate = together rate \n" ); document.write( "1/x + 1/(x+15) = 1/10 \n" ); document.write( "Multiply thru by 10x(x+15) to get: \n" ); document.write( "10(x+15) + 10x = x(x+15) \n" ); document.write( "20x + 150 = x^2+15x \n" ); document.write( "x^2-5x+150=0 \n" ); document.write( "(x-15)(x+10) = 0 \n" ); document.write( "Positive solution: \n" ); document.write( "x = 15 hrs (time required for 1st pipe to do the job alone) \n" ); document.write( "x+15 = 30 hrs (time required for the 2nd pipe to do the job alone) \n" ); document.write( "============ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |