document.write( "Question 1171761: given the equation of a circle with its center at (12,10), and that touches but does not cross the line above. That is, the radius is the distance from the point to line. (I'm a bit confused on where to start, I know the equation of a circle is (x-h)^2+(y-k)^2=r^2, but am a bit unsure on how to apply this. \n" ); document.write( "
Algebra.Com's Answer #796663 by Boreal(15235)\"\" \"About 
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We need to know the distance from the point to the line, which is not described further here.
\n" ); document.write( "Suppose it is 7 units.
\n" ); document.write( "then the equation of the circle is (x-12)^2+(y-10)^2=49, the radius squared.
\n" ); document.write( "Where it touches the line, the equation of the circle equals the equation of the line. Setting each equal to 0 then setting them equal to each other might help.
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