document.write( "Question 1171634: consider a binomial random variable X with n=5 and p=0.40
\n" ); document.write( "a. Find the probability distribution of X
\n" ); document.write( "b. Find P(X<3)
\n" ); document.write( "C. Find P(2<=X<=4)
\n" ); document.write( "d. Find the mean and the variance of X
\n" ); document.write( "

Algebra.Com's Answer #796629 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
mean is 5*0.4 or 2
\n" ); document.write( "variance is 2*0.6 or 1.2
\n" ); document.write( "-
\n" ); document.write( "probability x=0 is 0.6^5=0.07776
\n" ); document.write( "probability x=1 is 5*0.4*0.6^4=0.2592
\n" ); document.write( "for x=2 is 5C2*0.4^2*0.6^3=0.3456
\n" ); document.write( "for x=3 it is 5C3*0.4^3*0.6^2=0.2304
\n" ); document.write( "for x=4 it is 5*0.4^4*0.6=0.0768
\n" ); document.write( "for x=5 it is 0.4^5=0.01024\r
\n" ); document.write( "\n" ); document.write( "for x<3, add the probabilities of x=0,1,2
\n" ); document.write( "for 2 < x < 4, add the probabilities of x=2,3, 4
\n" ); document.write( "
\n" ); document.write( "
\n" );